- Montrer que l'on a également: $$\cos 2a + \cos 2b + \cos 2c =\sin 2a +\sin 2b +\sin 2c=0$$
Soit $a,b,c$ des nombres réels tels que:
$$\cos a + \cos b + \cos c =\sin a +\sin b +\sin c=0$$
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